PPT Slide

V

r

V0 =

38.5

MeV

b =1.93 fm

BE 2.2245

MeV

Simplified Deuteron : neutron binding in a square well potential

Solve for K.b and hence V0 given b and BE :

1

Kb

=

– 1

tan(Kb)

? ?[m.BE/?2] ? b

K 2 =

(V0 – BE)

m

?2

a 2 =

(BE)

m

?2

sin Kr

e –ar

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